12n^2+68n+80=0

Solution for 12n^2+68n+80=0 equation:

12n^2+68n+80=0

a = 12; b = 68; c = +80;
Δ = b2-4ac
Δ = 682-4·12·80
Δ = 784
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{784}=28$
$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(68)-28}{2*12}=\frac{-96}{24}
=-4
$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(68)+28}{2*12}=\frac{-40}{24}
=-1+2/3
$